?

Log in

No account? Create an account

Previous Entry | Next Entry

Last Day on Sale!

This is the last day The Emperor's Agent is on sale for $.99! If you were planning to get it for yourself or for a friend, go do it now because the price will go back to $4.99 tomorrow.

What some Amazon readers say:

Jo Graham continues to weave an intricate tapestry of historical research and fantastical speculation into a ripping yarn about a woman exploring all the facets of experience through many lifetimes. M.E. Hunter

It's the research that makes this book so great. Taking what we know about her real life and weaving it into a fabulous plot, the author gives us the life of a fascinating woman at a pivotal time in history. Mara Greengrass

Elza is quite a different heroine than in most stories. Beautiful daring but sharper than many heroines in fiction. Without spoilers she's not easy to label but she's very easy to read about. D. Flair

There aren't enough books out there like this, books where a woman is unapologetically female and powerful in her own right rather than conforming to what society tells her to be. Geonn Cannon

Elza is a secret agent, somewhere between Bond and one of LeCarre's broken spies, except she never loses herself in posturing - she gets things done. The historical background is immaculate, and there's no-one like Jo Graham for bringing historical characters to life. B. Winter

Comments

( 4 comments — Leave a comment )
just_ann_now
Dec. 13th, 2013 03:54 pm (UTC)
Done! (Done buying presents for everyone else, time to buy one for myself.)
jo_graham
Dec. 13th, 2013 09:00 pm (UTC)
I hope you enjoy it! I'd love to hear what you think.

Edited at 2013-12-13 09:01 pm (UTC)
raederlephoenix
Feb. 9th, 2014 10:38 am (UTC)
Question about book order and series
Is there any page that shows which books belong to which series and in what order? Not even wikipedia seems to know. I've been hunting everywhere.
jo_graham
Feb. 10th, 2014 03:18 pm (UTC)
Re: Question about book order and series
Thanks for asking! I just answered your question as today's post.
( 4 comments — Leave a comment )